The figure below gives the details regarding the power flow in synchronous motor.
Where
Power input to a synchronous motor is given by
P = 3VphIphcosΦ = √3VLILcosΦ.
In stator as per the diagram there will be core loss
and copper losses taking place. The remaining power will be converted to gross
mechanical power.
Hence Pm= Power input to the motor – Total losses in stator.
From the phasor
diagram we can write Power input /phase Pi = VphIphcosΦ
Mechanical power
developed by the motor Pm= EbIa cos ∟ Eb & Ia= EbIa cos(δ – Φ)
Assuming iron
losses as negligible stator cu losses = Pi - Pm
Power output
/phase = Pm – (field cu
loss + friction & windage loss +stray loss)
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